best method i would choose for these is the wolf method ...
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OpenStudy (anonymous):
Wolfram.....??/
OpenStudy (anonymous):
not quite aquainted with it!
OpenStudy (anonymous):
Dude, it's probably not my place to say but you're spamming right now.
OpenStudy (esshotwired):
STOP SPAMMING!
OpenStudy (anonymous):
Sorry.......
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OpenStudy (anonymous):
kinda Desperate!!
OpenStudy (anonymous):
@Preetha
OpenStudy (anonymous):
@King
OpenStudy (anonymous):
@mathtutoring22
OpenStudy (akashdeepdeb):
Which question?
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OpenStudy (anonymous):
its posted
OpenStudy (anonymous):
all of'em .....just the method to use
OpenStudy (akashdeepdeb):
Do you know the first one?
OpenStudy (anonymous):
yes
OpenStudy (akashdeepdeb):
Tell me the one you do not know and let me see if I can answer that.
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OpenStudy (anonymous):
also the 2 and 4th subdivisions of Q1
OpenStudy (anonymous):
IDK 3rd subdivision of Q1
OpenStudy (akashdeepdeb):
Q1 #2,3,4 ?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
Q1....3
Q2...none
Q3.....3 and 4
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OpenStudy (akashdeepdeb):
ok hold on
OpenStudy (anonymous):
Aye aye Cap'n!
OpenStudy (anonymous):
Q5.....1 and 2
jhonyy9 (jhonyy9):
for 1 - i)
let theta being x
2sin^2 x = 3cos x
hope you know that
sin^2 x +cos^2 x = 1
so this mean that sin^2 x = 1 - cos^2 x this subtituted will get
1 -cos^2 x = 3cos x
cos^2 x +3cos x -1 = 0 note cos x = t and will get
t^2 +3t -1 = 0
this quadratic you can solve it for t and after you will get these roots of you just need make it equal with cos x
so and calculi the x in these cases
jhonyy9 (jhonyy9):
hope so much that is understandably sure right
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OpenStudy (anonymous):
Thank u so much
OpenStudy (anonymous):
I kinda actually got that
OpenStudy (anonymous):
These r the ones I need
Q1....3
Q2...none
Q3.....3 and 4
OpenStudy (anonymous):
sry my mistake!
jhonyy9 (jhonyy9):
1 - iii)
how you have try it ?
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jhonyy9 (jhonyy9):
this is a system of equations
OpenStudy (anonymous):
well r=\[\sqrt{3}/\sin\]
jhonyy9 (jhonyy9):
sin (thetea) note x and rewrite this system and solve it for x
OpenStudy (anonymous):
that's not my problem..........Problem is gtin the proper solution set...with all the iffs and buts removed........lol..like checking the intervals....
jhonyy9 (jhonyy9):
sorry but i dont understand your last words
i think that you need to solve this system for theta and r is just a coeficient
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OpenStudy (anonymous):
for e.g............I get solutions as pi/3 and -pi/3
jhonyy9 (jhonyy9):
so and for the intervals you need to know where is defined sinus and wher not
OpenStudy (anonymous):
but the solution set will be pi/3..........similarly
OpenStudy (anonymous):
xactly
jhonyy9 (jhonyy9):
check it please your exercise newly because there have wrote on the end of this line iii) in what interval you need getting for theta
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OpenStudy (akashdeepdeb):
jhonyy9 (jhonyy9):
so if you will check it you see that -pi/3 not is right because theta not can being minus
OpenStudy (anonymous):
for e.g -pi/3=pi/3 for cos....r8???
jhonyy9 (jhonyy9):
hope this will help you
OpenStudy (anonymous):
-pi/3 is nthing but 2pi-pi/3...get me??
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OpenStudy (akashdeepdeb):
Did you get the image?
OpenStudy (anonymous):
yes........are these the solutions??
OpenStudy (anonymous):
pi/6,pi/3
OpenStudy (anonymous):
5pi/6,2pi/3
OpenStudy (anonymous):
that's wat I got...
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OpenStudy (anonymous):
is it r8...........considering the intervals???
OpenStudy (akashdeepdeb):
crect
OpenStudy (anonymous):
phew....
OpenStudy (anonymous):
so I think m on the r8 track....no more help needed guys..........Thanks a lot for the method.........
OpenStudy (anonymous):
THanks @jhonyy9
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OpenStudy (akashdeepdeb):
So no need to solve the other questions right?
OpenStudy (anonymous):
nope...........all good!!!I got the idea thanks to @jhonyy9 's idea and your problem solving @AkashdeepDeb
OpenStudy (akashdeepdeb):
:)
jhonyy9 (jhonyy9):
welcom
jhonyy9 (jhonyy9):
my pleasure
good luck
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