Question

Question:
Part A: Divide (9x^4y^3 + 3x^3y^2 - 6x^2y - 12x^2y^4) by -3x^2y. Show your work, and justify each step.

Part B: How would your answer in Part A be affected if the x2 variable in the denominator was just an x?

Part C: What is the degree and classification of the polynomial you got in Part A?

Answer 1

You could examine one numerator term at a time. Let's see the first one.

\(\dfrac{9x^4y^3}{-3x^2y}\)

Answer 2

So I have to divide 9x^4y^3 by -3x^2y ?

Answer 3

The first think I think you need to examine is this simple example \[\frac{ 10 }{ 5*2 } \] can you break this down somehow?

Answer 4

Perhaps the word "divide" is scary? Don't say it. Just simplify the fraction as it has been presented.

\(\dfrac{9x^{4}y^{3}}{−3x^{2}y} = \dfrac{9}{-3}\cdot\dfrac{x^{4}}{x^{2}}\cdot\dfrac{y^{3}}{y}\)

Does that look any better?

Answer 5

@tkhunny Sooo it'd be -3x^6y^4 :)

Answer 6

@knivez I'm confused... :/

Answer 7

you can do \[ \frac{ 10 }{ 5 } = 2\] and then do \[\frac{2}{2} = 1 \] and then you can apply this same method to your problem.

Answer 8

Ohh okay :) Thank you.

Answer 9

so first divide by \[-3x^{2}\] and then divide by y

Answer 10

Why would you ADD the exponents in a division problem?

\(x^{2}\cdot x^{4} = x^{2+4} = x^{6}\)

\(\dfrac{x^{4}}{x^{2}} = x^{4 - 2} = x^{2}\)