Question

Need help with algebra plz

Answer 1

yes, what do you need help with?

Answer 2

Choose the equation of the line passing through the point (1, -5) and perpendicular to y = 1 fifthx - 10.

y = 5x + 10

y = 5x

y = -5x - 10

y = -5x

Answer 3

The original slope is 1/5

the perpendicular slope is -5/1 or just -5 (flip the fraction and flip the sign to go from 1/5 to -5/1)

so m = -5

Answer 4

the line must pass through (1,-5), so

x = 1
y = -5

Answer 5

y = mx+b

y = -5x+b ... plug in the given slope

-5 = -5*(1) + b ... plug in x = 1 and y = -5

now solve for b

Answer 6

-5?

Answer 7

-5 = -5*(1) + b

-5 = -5 + b

b = ???

Answer 8

be stands for y intercept but this is where i am having problems how do you solve b

Answer 9

-5 + b is the same as b + (-5) or b - 5

Answer 10

so

-5 = -5 + b

turns into

-5 = b - 5

Answer 11

you can flip the equation to get

b - 5 = -5

Answer 12

so b = ??

Answer 13

wouldnt i turn it into point slope form like so \[y + 5 = -5(x - 1)\]

Answer 14

then

Answer 15

that's one way to do it, now solve for y

Answer 16

\[y + 5 =-5x + 5\]

Answer 17

good, keep going

Answer 18

\[y = -5x\]

Answer 19

perfect

Answer 20

so D

Answer 21

correct

Answer 22

yay thank you so much

Answer 23

you're welcome