Graph the inequality
y\[y \le -\frac{ 1 }{ 2 }x ^{2}+x+4\]
Can you show me how you solved it? I need to also find the Axis of Symmetry: Vertex: y-int: Is this a graph with a Maximum or Minimum? Domain: Range:
I think the y-int is (0,-4) because I got rid of the negative in the the first x term which changed the signs of all the other terms.
Yes, y-intercept is (0,4). To get y-intercept, set x = 0 and compute y.
How is it positive 4?
Would it not be -4 because you get rid of the negative in the first x term?
Since they are asking for vertex, put y = −1/2x^2 + x + 4 in vertex form. To do that complete the square.
Could you remind me what vertex form is?
y = a(x - h)^2 + k where (h,k) is the vertex. To put it in vertex form you need to complete the square.
ah ok. Lemme do that real fast for completing the square.
ok so the vertex form I have come up with this now is y=-2(x-1/2)^2-33/2
Is that correct?
how did the -1/2 coefficient of x^2 become -2?
huh?
U mean the number outside the parenthesis?
yes. original equation has -1/2x^2. If you expand your answer: -2(x-1/2)^2-33/2 you will get -2x^2 ...
I don't ever expand my equation.
Oh wait. I can explain.
My teacher said that if there is a number in front of x^2 in the original equation, to always get rid of it. Thus I divided everything.
What I am telling you is your answer is not correct because -1/2x^2 has now become -2x^2.
yes. This is how I will do it. Complete the square: −1/2x^2 + x + 4 We want to make the coefficient of x^2 +1. So factor out -1/2. Which means the other terms have to be divided by -1/2 which is same as multiplying by -2: −1/2x^2 + x + 4 = -1/2(x^2 - 2x - 8) now complete the square.
Alright so I got a bigger space to work on now, is this right? y=-1/2(x-1)^2-9/2
the last term should be +9/2
But I subtracted 9 from both sides..
-1/2(x^2 - 2x - 8) to complete the square take coefficient of x term and divide by 2: -2/2 = -1. This -1 will go inside the parenthesis to be squared and you subtract (-1)^2 -1/2(x^2 - 2x - 8) = -1/2{ (x-1)^2 - (-1)^2 - 8 } = -1/2{ (x-1)^2 - 1 - 8 } = -1/2{ (x-1)^2 - 9 } = -1/2(x-1)^2 + 9/2
That is my work..^
The mistake is in the very last line. When you divide -9 by -2, it is +9/2
OHHH!!!!
y = -1/2(x-1)^2 + 9/2 compare this to y = a(x - h)^2 + k which has the vertex at (h,k). What is the vertex of y = -1/2(x-1)^2 + 9/2
(1,9/2)
I think I have the graph down now. Thank you so much for your help you have no idea how much I needed this :)
you are welcome.
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