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Mathematics 16 Online
OpenStudy (karatechopper):

Graph the inequality

OpenStudy (karatechopper):

y\[y \le -\frac{ 1 }{ 2 }x ^{2}+x+4\]

OpenStudy (karatechopper):

Can you show me how you solved it? I need to also find the Axis of Symmetry: Vertex: y-int: Is this a graph with a Maximum or Minimum? Domain: Range:

OpenStudy (karatechopper):

I think the y-int is (0,-4) because I got rid of the negative in the the first x term which changed the signs of all the other terms.

OpenStudy (ranga):

Yes, y-intercept is (0,4). To get y-intercept, set x = 0 and compute y.

OpenStudy (karatechopper):

How is it positive 4?

OpenStudy (karatechopper):

Would it not be -4 because you get rid of the negative in the first x term?

OpenStudy (ranga):

Since they are asking for vertex, put y = −1/2x^2 + x + 4 in vertex form. To do that complete the square.

OpenStudy (karatechopper):

Could you remind me what vertex form is?

OpenStudy (ranga):

y = a(x - h)^2 + k where (h,k) is the vertex. To put it in vertex form you need to complete the square.

OpenStudy (karatechopper):

ah ok. Lemme do that real fast for completing the square.

OpenStudy (karatechopper):

ok so the vertex form I have come up with this now is y=-2(x-1/2)^2-33/2

OpenStudy (karatechopper):

Is that correct?

OpenStudy (ranga):

how did the -1/2 coefficient of x^2 become -2?

OpenStudy (karatechopper):

huh?

OpenStudy (karatechopper):

U mean the number outside the parenthesis?

OpenStudy (ranga):

yes. original equation has -1/2x^2. If you expand your answer: -2(x-1/2)^2-33/2 you will get -2x^2 ...

OpenStudy (karatechopper):

I don't ever expand my equation.

OpenStudy (karatechopper):

Oh wait. I can explain.

OpenStudy (karatechopper):

My teacher said that if there is a number in front of x^2 in the original equation, to always get rid of it. Thus I divided everything.

OpenStudy (ranga):

What I am telling you is your answer is not correct because -1/2x^2 has now become -2x^2.

OpenStudy (ranga):

yes. This is how I will do it. Complete the square: −1/2x^2 + x + 4 We want to make the coefficient of x^2 +1. So factor out -1/2. Which means the other terms have to be divided by -1/2 which is same as multiplying by -2: −1/2x^2 + x + 4 = -1/2(x^2 - 2x - 8) now complete the square.

OpenStudy (karatechopper):

Alright so I got a bigger space to work on now, is this right? y=-1/2(x-1)^2-9/2

OpenStudy (ranga):

the last term should be +9/2

OpenStudy (karatechopper):

But I subtracted 9 from both sides..

OpenStudy (ranga):

-1/2(x^2 - 2x - 8) to complete the square take coefficient of x term and divide by 2: -2/2 = -1. This -1 will go inside the parenthesis to be squared and you subtract (-1)^2 -1/2(x^2 - 2x - 8) = -1/2{ (x-1)^2 - (-1)^2 - 8 } = -1/2{ (x-1)^2 - 1 - 8 } = -1/2{ (x-1)^2 - 9 } = -1/2(x-1)^2 + 9/2

OpenStudy (karatechopper):

OpenStudy (karatechopper):

That is my work..^

OpenStudy (ranga):

The mistake is in the very last line. When you divide -9 by -2, it is +9/2

OpenStudy (karatechopper):

OHHH!!!!

OpenStudy (ranga):

y = -1/2(x-1)^2 + 9/2 compare this to y = a(x - h)^2 + k which has the vertex at (h,k). What is the vertex of y = -1/2(x-1)^2 + 9/2

OpenStudy (karatechopper):

(1,9/2)

OpenStudy (karatechopper):

I think I have the graph down now. Thank you so much for your help you have no idea how much I needed this :)

OpenStudy (ranga):

you are welcome.

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