Question

Write an equation of the line through (3,-2) and perpendicular to 5y=x-10.

Answer 1

Anyone?

Answer 2

do you have an idea how to do it

Answer 3

I'm actually having a tough time with linear inequalities and graphing

Answer 4

slope = 1/5
therefore
(y+2)/(x-3)=1/5
now solve it and get the answer
'

Answer 5

sorry guys slope is -5 else everything is same

Answer 6

The problem is, is that I don't understand how to solve it or how you ended up with -5.

Answer 7

since line is perpendicular to the given line therefore the product of two slopes is minus one therefore if given line has a slope 1/5 other which we are going to find that must be -5

Answer 8

Yes. Slope of perpendicular line is - 1/slope = -5.
Next solve y = -5x + b for b, knowing x=3, y=-2

Answer 9

So it would be -2 = -5x + 3? Did I get that correct?

Answer 10

or wait. I meant -2=-5x(3) + b

Answer 11

5y = x -10 can be rewritten as y=1/5 x -2. the slope of this equation is 1/5. The slope of a line perpendicular would be (i think it's called the recpriocal) -5.

now use the equation: (Y-y) = m(X-x) where y=-2 and x=3.

Answer 12

yeah very right

Answer 13

y-2=-5(x-3)?

Answer 14

close.
look at y-2.

Answer 15

y-(-2)=-5(x-3)

Answer 16

or y+2=-5(x-3) which I think would then come out to: y+2=-5x+15

Answer 17

In high school, my teachers wanted it written: y = -5(x-3)-2, because that is how it is easiest to "see" the graph.

Answer 18

Thank you to everyone who has helped. I really appreciate you all for taking the time and effort to give me insight into this problem.