a(subscript(n+1)) = [na(sub(n))] / [n+2]

First 5 terms. (I'm struggling to do it because the a(sub(n+1)) thing is super confusing me.)

Question

a(subscript(n+1)) = [na(sub(n))] / [n+2]

First 5 terms. (I'm struggling to do it because the a(sub(n+1)) thing is super confusing me.)

campbell_st · Answer

so what you have is

$$a_{n +1} = \frac{na_{n}}{(n + 2)}$$

campbell_st · Answer

so are you given an initial value of n or a

anonymous · Answer

$$a _{n+1} = \frac{ na _{n} }{ n+2 }$$

oh yeah. sorry. a1 = 2.

campbell_st · Answer

because all ot means to me

n = 1 $$a_{2} = \frac{a_{1}}{3}$$

n = 2

$$a_{3} = \frac{2 \times a_{2}}{4} $$

n = 3

$$a_{4} = \frac{3 \times a_{3}}{5}$$

etc

campbell_st · Answer

so just subsitute a1into the 1st equation to find a2... and then you can proceed to find all the others.

campbell_st · Answer

so for n = 1

$$a_{2} = \frac{1 \times 2}{3}$$

get a value

n = 2

$$a_{3} = \frac{ 2 \times a_{2}}{4}$$

and continue

anonymous · Answer

my answer is: a1=2. a2=2/3. a3=1/3. a4=1/5. a5=1/15.

anonymous · Answer

thank you.

campbell_st · Answer

it seems to make sense... well done...