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Mathematics 17 Online
OpenStudy (anonymous):

help please... I will attach the practice test questions...

OpenStudy (anonymous):

OpenStudy (tkhunny):

Please attach your practice test answers and efforts. If you really have no idea on any of them, you're toast.

OpenStudy (anonymous):

well i worked on # 2 and 3 and i said #2 diverges and #3 converges ?? but i have no idea for # 1 can you helP???

OpenStudy (anonymous):

/loser66/ cn you help ?:s

OpenStudy (kc_kennylau):

ok firstly calculate \[\int_0^\infty \frac{\tan^{-1}x}{1+x^2} dx\]

OpenStudy (kc_kennylau):

Hint: \(\Large\int\frac1{1+x^2}dx=\tan^{-1}x\)

OpenStudy (anonymous):

i found it diverges but i'm wrong so if you know the answer cn you please explain it to me step by step???

OpenStudy (kc_kennylau):

\[\hspace{15pt}\large\int_0^\infty\frac{\tan^{-1}x}{1+x^2}dx\]\[\Large=\int_0^\infty\tan^{-1}x\hspace{5pt}d(\tan^-1x)\]\[\Large=\frac12\left[\left(\tan^{-1}x\right)^2\right]_0^\infty\]\[\Large=\frac12\left[\left(\frac\pi4\right)^2-0^2\right]\]\[\Large=\frac{\pi^2}{32}\]

OpenStudy (kc_kennylau):

Since this is finite, the series therefore converges

OpenStudy (anonymous):

thank you so much

OpenStudy (kc_kennylau):

no problem :)

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