Question

Trigonometry help please! im bad at this.

Answer 1

60 degrees is opposite to the leg which has a value of 12.
First, we need to find z, by using the sine function.
It states sine theta = opposite / hypotenuse

So:
sin 60° = 12/z
Can you solve for z?

Answer 2

Here is a nice way of looking at it
When you have a fraction and variable is in the denominator you cross multiply or if it is equal to a fraction so:
\[\Huge \sin~60° = \frac{ 12 }{ z}\]
\[\Huge z = \frac{ 12 }{ \sin~60° }\]

Answer 3

Use your scientific calculator and find out what sin 60 ° is then just simplify that.

Answer 4

okay so z = 12sqrt26

Answer 5

that value is wrong..
z = 8 √3

anyways now you have two of your values in a right triangle
from here just use the Pythagorean theorem
\[\huge a^2 +b^2 = c^2\]
\[\huge (12)^2 + b^2 = (8\sqrt{3})^2\]
solve for b, in this case b = y.

Answer 6

im so confused right now D:

Answer 7

Solve for b. umar

Answer 8

I can't do all the work >.>

Answer 9

The Pythagorean theorem states:
\[\huge a^2 + b^2 = c^2\]

Answer 10

isnt b = 12? in the picture?

Answer 11

It's either, it doesn't matter a^2 + b^2 = c^2
you could say a = 12 ,or b = 12
you still have one missing value.

Answer 12

and for this case if you really want to be on "term" a = 12 not b.

Answer 13

this isn't a 45-45-90 triangle it's a 30-60-90 triangle so the legs aren't congruent.

Answer 14

You could use the 30-60-90 triangle theorem for this as well, or use trigonometric functions sine and cosine to solve for the missing variables.

Answer 15

You'll end up with the same exact values.

Answer 16

omfg Dx I got 18. can you give me the formula for b?

Answer 17

\[\huge b^2 = c^2 - a^2\]

Answer 18

so b = -48?

Answer 19

no no ..

Answer 20

omfg im so bad at this

Answer 21

\[\huge b^2 = (8 \sqrt{3})^2 - (12)^2\]

Answer 22

I can tell.

Answer 23

Hint, 12^2 = 144
and (8√3)^2 = 192.

Answer 24

i did that tho!! on a calculator..

Answer 25

so b = 18.3?

Answer 26

b^2 = 48
b = √48

Answer 27

b = 4√3

Answer 28

lol fml

Answer 29

Umar, a calculator might help, please learn how to use it -_-

Answer 30

or at least find the radical value -.- through algebra

Answer 31

so lucky that was the last question :( and im just bad at math bruh, trigonometry to be exact

Answer 32

\[\huge √48 = \sqrt{16 * 3} = 4\sqrt{3}\]

Answer 33

thanks alot. im gonna re-read the chaptor and go on khan academy or something.

Answer 34

we're not done yet, umar.

Answer 35

y = 4 √3
z = 8√3

what is x?

Answer 36

WOOOOOW omg

Answer 37

Umar, you need to pay attention .

Answer 38

lolol

Answer 39

okay teacher :( im just sleepy i guess. so we do the same for x??

Answer 40

anyways im too tired to give you a very verbose paragraph explaining that..
you should know this

its a 45-45-90 triangle

its hyp = 12
so
x = 12√3
h = L √3

Answer 41

you don't need trig for this, just able to remember these theorems or google them lol

Answer 42

30-60-90 http://www.regentsprep.org/regents/math/algtrig/ATT2/Ltri30.htm
45-45-90 http://www.regentsprep.org/regents/math/algtrig/ATT2/Ltri45.htm

Answer 43

okay thanks. imma read that right now.

Answer 44

mk