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Mathematics 10 Online
OpenStudy (anonymous):

Shortcut to find the following sum (in the next post):

OpenStudy (anonymous):

\[\sum_{n=0}^{25}\frac{ 1 }{ 4^{n} }\]

OpenStudy (anonymous):

Sum from n = 0 to 25, (1/4^n)

OpenStudy (anonymous):

The answer should be 1.33

OpenStudy (kc_kennylau):

This is just a geometric progression with a=1 and r=0.25 and n=26 :)

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

I got it now :D

OpenStudy (kc_kennylau):

The formula for the sum is \(\dfrac{a(1-r^n)}{1-r}\) if r<1 or \(\dfrac{a(r^n-1)}{r-1}\) if r>1 (The two formulas are the same)

OpenStudy (kc_kennylau):

no problem :)

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