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Shortcut to find the following sum (in the next post):
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\[\sum_{n=0}^{25}\frac{ 1 }{ 4^{n} }\]
Sum from n = 0 to 25, (1/4^n)
The answer should be 1.33
This is just a geometric progression with a=1 and r=0.25 and n=26 :)
ok thanks
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I got it now :D
The formula for the sum is \(\dfrac{a(1-r^n)}{1-r}\) if r<1 or \(\dfrac{a(r^n-1)}{r-1}\) if r>1 (The two formulas are the same)
no problem :)
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