Question

Question?
http://prntscr.com/29b6ea

Answer 1

standard form of circle :-

\(\large (x - \color{green}{h}) + (y-\color{green}{k}) = \color{red}{r}^2\)

Answer 2

radius = \(\large \color{red}{r}\)
center = \(\large \color{green}{(h, k)}\)

Answer 3

k

Answer 4

compare ur equation wid above

Answer 5

we dont have k

Answer 6

0 is there for the orphaned additions

Answer 7

:P

Answer 8

ok so it means
(x-5)+(y-0) = 19^2

Answer 9

Yes,

\((x-5)^2 + y^2 = 38 \)

\((x-5)^2 + (y-0)^2 = 38 \)

Answer 10

ugh no, 19^2 is not equal to 38 ok

Answer 11

\(\large (x-5)^2 + (y-0)^2 = \sqrt{38}^2 \)

Answer 12

19^2 = 361

Answer 13

@ganeshie8 you're last equation is the same as what i just wrote...

Answer 14

@kc_kennylau u wrote something ?

Answer 15

Did you read the replies?

Answer 16

its not showing up here :|

Answer 17

http://openstudy.com/study#/updates/52a2db73e4b0256dd097983a

Answer 18

I see only my/lily replies hmm

Answer 19

Well it shows up on mine did you look up above all your work?

Answer 20

@Victoria_Davis_2018 she opened another question so that's why it's not here

Answer 21

Yes I see that now sorry @ganeshie8

Answer 22

i see that on my screen

Answer 23

oh ok cool :)
i was worried if the OS is not working again lol

Answer 24

why cant i see the replies they are not loading up let log out then log in wait

Answer 25

hey Lily we're good, lets continue...

Answer 26

oh ya i see that was in previous post ok now i get it :)

Answer 27

Yeah sorry I can be really stubborn sometimes, really sorry

Answer 28

so the correct option is J

Answer 29

nope in \(x-\color{green}5\) the \(\color{green}h\) is 5 :)

Answer 30

So H then

Answer 31

why x-5 so -5 is negative

Answer 32

But in x - 5 when you take the x away it is -5

Answer 33

because it's \(\Large (x-\color{green}{h})^2\) not \(\Large (x+\color{green}{h})^2\) :)

Answer 34

ok

Answer 35

Well I guess that is a pretty good reason so it is F?

Answer 36

yes :)

Answer 37

Ok well I say that was a pretty good guess because I don't know how to do all this

Answer 38

ok but why F i mean \[\sqrt{38}^2\]
so the square and square root cancel themselves so it will be just 38

Answer 39

yep, but \(\Large\color{red}{r}^2\) is required, not \(\Large\color{red}{r}\), so we have to change \(38\) to something squared :)

Answer 40

Sorry I know these are not related to the topic, but they could help someone

Answer 41

Jesus will always be king.

Answer 42

thanks

Answer 43

no problem :)