Find the product of (3x - 4)(2x2 + 2x - 1)
First distribute the 3x to the terms in the second polynomial.
Distribute the 3x-4 to every term. (3x-4)2x^2+(3x-4)2x-(3x-4)
Then, distribute the -4 to the terms in the second polynomial.
Combine the terms to make the answer.
Make sure you take care when dealing with the negatives. But let me do the first set for you. (3x-4)2x^2= 6x^3-8x^2
Does that make sense?
No
Which one is it then? 6x3 + 2x2 - 5x + 4 6x3 + 14x2 - 11x + 4 6x3 - 14x2 - 5x + 4 6x3 - 2x2 - 11x + 4
You "distribute" the 3x-4 to each term. So you give each of the terms inside a copy of (3x-4). Now you only need to work with one term at a time. I did the first term for you, but you said it didn't make sense. Multiply the 2x^2 by 3x, then add it to -4*2x^2.
Which one is it then? 6x3 + 2x2 - 5x + 4 6x3 + 14x2 - 11x + 4 6x3 - 14x2 - 5x + 4 6x3 - 2x2 - 11x + 4
I don't believe in giving out answers. You should understand it so you can do it again on your own.
So now, try the second term, (3x-4)2x
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