Question

Identify the horizontal asymptote of f(x) = x^2+6x-9

Answer 1

hello again

Answer 2

Hello. I need to know how to find horizontal asymptotes.

Answer 3

is x^2 + 6x -9 the whole problem?

Answer 4

no, sorry, I typed in the wrong problem it is actually 6x-7/11x+8

Answer 5

I know how to solve the above problem, which wasn't the whole question also :P

Answer 6

okay
A horizontal asympotote is found by comparing the degree of the numerator to the degree of the denominator

Answer 7

what can you tell me about the degrees

Answer 8

The degrees are the highest exponent of a coefficient, which appears to be 1 and 1.

Answer 9

correct and when the degrees of the numerator and the denominator are the same you do this

Answer 10

y = 6/11

Answer 11

Is that the answer?

Answer 12

can it be simplified any further?

Answer 13

No because they do not have any common factors.

Answer 14

correct then 6/11 is your answer

Answer 15

Thank you!

Answer 16

no problem mate