Binomial expansion help!! calculate the coefficient of x^2y^6 in the expansion of (x+y)^8
\[x^8+8 x^7 y+28 x^6 y^2+56 x^5 y^3+70 x^4 y^4+56 x^3 y^5+28 x^2 y^6+8 x y^7+y^8 \]
So the coefficient of x^2y^6 is 28. right?
So the coefficient of x^2y^6 is 28. right? Yes.
If you have access to the Mathematica program you will find that it is easier to just ask it to expand (x+y)^8 . Takes 63 millionths of a second for the expansion on a mid 2010 IMac.
Note also that all the coefficients can be found using $$ \binom{8}{2}=\binom{8}{6}=28 $$ Where 8 is the total power of the term (i.e. 2+6) and 2 is the degree of either of the small terms (2 or 6)
As another example, to determine the coefficient of $$ x^3 y^5 $$ take $$ \binom{8}{3}=\binom{8}{5}=56 $$
That makes sense. Thanks for the help @ybarrap and @robtobey
@studygeek15 Learn ybarrap's method if you are restricted to paper and pencil in a test enviornment
yw
@ybarrap Thank you for the medal.
you deserve it, we both contributed
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