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Mathematics 6 Online
OpenStudy (kewlgeek555):

HELP - THIS IS DUE TONIGHT. ;-; A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, determine which system of inequality best explains whether the company can build 20 child bikes and 6 adult bikes in the week.

OpenStudy (kewlgeek555):

a. No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100 b. No, because the bike order does not meet the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100 c. Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100 d. Yes, because the bike order meets the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100

OpenStudy (kewlgeek555):

@ganeshie8 @phi @agent0smith @campbell_st @terenzreignz @ranga

OpenStudy (kewlgeek555):

I'm sooooo sorry for wasting your time. I think I got the answer. If you'd like, I can show what I think is correct.

OpenStudy (agent0smith):

child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. for testing, 4 hrs per child bike, 4 per adult 4c + 4a ≤100 for building, 4 hrs per child bike, 6 hrs per adult 4c + 6a ≤120 20 child bikes and 6 adult... check if c=20 and a=6 work in both those inequalities.

OpenStudy (kewlgeek555):

So I made the system:\[4c+6a \le120\]\[4c+4a \le100\]So, that means it cannot be B. Now to do the math...and plug in the values: \[4(20)+6(6)\]\[80+6(6)\]\[80+36\]\[116\]Okay, thats good.\[4(20)+4(6)\]\[80+4(6)\]\[80+24\]\[104\]uh-oh, so the answer must be A...

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