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Find the summation of the finite geometric series below. (It should equal 3.75)
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\[\sum_{i = 1}^{10}5(\frac{ -1 }{ 3 })^{i-1}\]
Through the equation, I keep getting 1.5
In this case, the first term is a = 5 and the common ratio is r = -1/3
you would then plug these values into the nth partial sum formula \[\Large S_n = a\left(\frac{1-r^n}{1-r}\right)\]
oh and in this case, n = 10 since you want the 10th partial sum
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I got it now, thanks.
np
I think I was multiplying it by 2 for some reason
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