If we wish to have a 95% confidence interval, what would be the value of the confidence coefficient?
http://mathworld.wolfram.com/ConfidenceInterval.html $$ \mu-n\sigma<x<\mu+n\sigma $$ Where \(\mu\) is the mean and \(\sigma\) is the standard deviation. So to compute the 95% confidence interval, you need both these values. The link above that n=1.96 will provide the 95% confidence interval. To determine in general to confidence coefficient for any probability P other than .95, use $$ n=\sqrt 2 erf^{-1}(P) $$ Where \(erf^{-1}(P)\) is the inverse error function evaluated at P. For example, in your problem, P=.95 so http://www.wolframalpha.com/input/?i=%28inverse+error+function+.95%29*sqrt%282%29
Join our real-time social learning platform and learn together with your friends!