Question

Find the area under the graph of f over [-2,2]

f(x)={4-x^2, if x<0
4, if x>0

Answer 1

Sorry, \[4 if x \ge 0\]

Answer 2

I got 9.3, not sure where I went wrong.

Answer 3

It looks as if you will need to set up 2 separate integrals.
First, integrate the top function (for x<0) on [-2,0]. --> 16/3
Then, add it to the integral of the bottom part on [0,2]. --> 8

Your exact answer is 40/3, or 13.333333333333...

Answer 4

YES. 40/3

Answer 5

Okay :O So then for the area bounded by y=x^2 and y=4

Answer 6

Intersects are (-2,4) and (2,4) so then my interval is -[2,2]

Answer 7

\[\int\limits_{-2}^{2}x^2dx-\int\limits_{-2}^{2}4dx\]