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Mathematics 9 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

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Directrix (directrix):

Triangle JMN is an equilateral triangle of side 10. The distance from J to segment MN is the same as the length of the red altitude drawn from M to segment MN in triangle JMN.

OpenStudy (anonymous):

so.. I need to find the altitude?

OpenStudy (anonymous):

is it just the same length.. which is 10?

Directrix (directrix):

The altitude drawn to the base of this triangle bisects the base. You can find the altitude using the 30-60-90 theorem or by using the Pythagorean Theorem. ** The answer is not 10.

OpenStudy (anonymous):

oh, pythagorean? alright.. :)

Directrix (directrix):

You can crank out: 10² = 5² + h² Solve for h.

Directrix (directrix):

Or, you can apply the 30-60-90 theorem

OpenStudy (anonymous):

5(sqrt3) or 8.55 am i right?

Directrix (directrix):

>>>>5(sqrt3) or 8.55 5 SQR(3) is 8.66 approx

OpenStudy (anonymous):

oh right ,another typo .__. thank youuu :D

Directrix (directrix):

Glad to help.

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