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Let h(x)=xe^x. Find d/dt h(x) if x=x(t)
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Can yo find d/dx h(x) ?
*you
Note that chain rule will come in handy here. :-)
Note: \[\frac{d}{dt} h(x) = (\frac{d}{dx}h(x)) \times(\frac{d}{dt}x)\], where x = x(t)
So far I got d/dt x(e^x d/dt x + x d/dt e^x)
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My advice is to find \(\frac{d}{dx} (h(x))\) first. Then, find \(\frac{d}{dt} x(t) \). Finally, multiply the two answers and replace all x by x(t)
Oh I see. Thanks a lot!
FYI, that's chain rule as @ChristopherToni has said.
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