Question

Equation of the tangent line of the graph 8x/(x^2+1) at the origin and (-1,-4)
These are two separate answers

Answer 1

Nevermind I know how :)

Answer 2

@kc_kennylau actually, I got it for (-1,-4) but not for the origin!

Answer 3

nevermind, I think it's 8x and 4x!

Answer 4

sorry for correcting, but never mind is two words

Answer 5

Haha I honestly did not know that..

Answer 6

If:\[\log_{b}4=1.386\]
\[\log_{b}7=1.946\]

what is\[\log_{b}28\]

Answer 7

Just 1.386*1.946?

Answer 8

Yep

Answer 9

How do I find velocity and acceleration when only given speed?

Answer 10

Maybe not related, but this is interesting:
Unit of distance: \(\large m\cdot t^0\)
Unit of speed (velocity): \(\large m\cdot t^{-1}\)
Unit of acceleration: \(\large m\cdot t^{-2}\)

Answer 11

but speed is the same as velocity?

Answer 12

Idk ;_;

Answer 13

http://gyazo.com/79d312d9c3243727e7c78786a5130f74

Answer 14

@Kainui

Answer 15

s is not speed, s is displacement (distant)

Answer 16

Clearly I'm dumb and it's 4 a.m :P

Answer 17

Important formulas:
\[\frac{ds}{dt}=v\]\[\frac{dv}{dt}=a\]

Answer 18

So I assume you know how to do that? :P

Answer 19

So basically a is second derivative

Answer 20

That's what I figured it was but I didn't want to mix them up

Answer 21

yep :)

Answer 22

How do you find the derivative of (lnx)^2?

Answer 23

2lnx? that's it? haha i mean im sure theres more steps

Answer 24

Chain rule :)

Answer 25

2 * ln x * (1/x)

Answer 26

I hate quotient rule xD I actually hate all rules besides power

Answer 27

sorry back

Answer 28

yep

Answer 29

but you have to simplify it

Answer 30

2lnx/x

Answer 31

sorry back yep

Answer 32

And then 2ln(8)/8=0.519

Answer 33

yep

Answer 34

http://gyazo.com/c45644d8437428e85dfd85b9e056275d

Answer 35

So then input y=0.519...x+b and input the (8,0) for x and y, solve for b and thats my y intercept

Answer 36

Just not sure how i'd do this without a computer since the numbers are extremely long

Answer 37

you have a calculator

Answer 38

you don't need so many places. 4 is actually enough.

Answer 39

Would you say the 2nd part of B is asking for the derivative of P'(x) when x=70 as in, no delta included, or with the delta?
http://gyazo.com/798ed926afb065b09f95a5675a583017

Answer 40

@kc_kennylau

Answer 41

\[\Delta P\approx P'(x)\cdot\Delta x\]

Answer 42

Wait, I did it wrong -_- forgot about R(x)

Answer 43

i see

Answer 44

So the derivative of P'(x) is -0.02x+1.4

Answer 45

Of P(x) not of P'(x)

Answer 46

sorry back

Answer 47

I suck at these with delta

Answer 48

what's P(x) anyway

Answer 49

brb

Answer 50

-0.01x^2+1.4x-50

Answer 51

yep

Answer 52

So to find delta P, I do what?

Answer 53

\[\Delta P\approx P'(x)\cdot\Delta X\]

Answer 54

sorry brb

Answer 55

-0.02x+1.4*1..?

Answer 56

-0.02(70)+1.4*1..?

Answer 57

brackets bro, brackets

Answer 58

[-0.02(70)+1.4]*1

Answer 59

well anyway theyre equal

Answer 60

sorry really be right back

Answer 61

Haha it's okay im getting off, 5:30 a.m it's time for me to take a nap then get up and study some more for my final!

Answer 62

hi lol back