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evaluate 4 / (sqrt (1+2x))^3
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i don't know whether the answer is \[\frac{ -8 }{ \sqrt{1+2x} } +C\] or -\[\frac{ -4 }{ \sqrt{2x+1} } +C\]
evaluate \[ \int\limits_{}^{}\frac{ 4 }{ (\sqrt{1+2x})^{3} } dx\]
its not \[\int\limits\limits_{}^{} \frac{ 4 }{ (\sqrt{1+2x})^{3/2} } dx\]
its \[\int\limits\limits_{}^{} \frac{ 4 }{ (\sqrt{1+2x})^{3} } dx\]
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\[\Large(\sqrt{1+2x})^3=(1+2x)^{\frac32}\]
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