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Mathematics 16 Online
OpenStudy (anonymous):

Vectors' sum : If |a|=5, |b|=12, |c|=13; and a+b+c = 0, find the value of a.b + b.c + c.a I'm getting the answer as -169, whereas the answer given is -15. Where am I going wrong?

OpenStudy (kc_kennylau):

If |a|=5 and |b|=12 and |c|=13 how can a+b+c ever be 0

OpenStudy (sumeer):

its vector sum :D

OpenStudy (anonymous):

a, b, c are vectors.

OpenStudy (kc_kennylau):

oh sorry

OpenStudy (anonymous):

It's okay :D

OpenStudy (kc_kennylau):

|dw:1386515950056:dw| I assume this pic is correct?

OpenStudy (kc_kennylau):

sorry i'm not quite good in vectors

OpenStudy (sumeer):

yea i think so

OpenStudy (anonymous):

I'd show you guys how I worked it out .. given, a=5, b=12, c=13 ..and a+b+c = 0 => (a+b+c)^2=0 => a^2 + b^2 + c^2 + 2(a.b+b.c+c.a)=0 => a.b + b.c + c.a = -338/2 = -169

OpenStudy (sumeer):

|dw:1386516238353:dw| i think this is possible too, this may cause the double answer, i hope it its not true it'll lead u an inspiration

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