Question

help

Answer 1

@dumbcow @phi I need help with part A. it seems like its pretty straight forward but im getting the wrong answers.

Answer 2

add up scrap rates .... 15+7+7 = 29%
so only 71% of original is output

0.71 x = 496

Answer 3

15+7=22

Answer 4

o do they mean 7 for each or 7 for both?

Answer 5

7 for each step2 and step3

Answer 6

so whats the final answer? im confused

Answer 7

x = 496 / 0.71

Answer 8

I tried that. its not correct.

Answer 9

i got 699 when rounding up

Answer 10

oh well i guess i misread it...maybe its 496/.78

Answer 11

no :/

Answer 12

ugh i hate this hw assignment

Answer 13

ok then that means the 7% is of new total after taking the 15%

Answer 14

i tried that too.
i did:
496 * .15 = #
then take that # and * .07 to get another #
finally add the two #s together and add them to 496

Answer 15

no you wouldnt take 7% of 496* .15 , it would be 7% of remaining units .85 *496

also i really think its 7% for each step because it does say 3 step process so there is percent for each step

--> (.93)(.93)(.85X) = 496
--> X = 496 / (.93)(.93)(.85)

try that

Answer 16

That's right! :D

Answer 17

Thanks! I might need some more help with a different problem here in a few

Answer 18

ok

Answer 19

this is how i had the prob set up:
mu +- ( z * sigma/sqrt of n)
.96 +- ( .3340 * .04/sqrt of 27)

Answer 20

i think im using the wrong z value

Answer 21

everything else is given pretty much

it does say 96 % so i used the z-table an that's how i got .3340

Answer 22

yeah use diff z value.... .96 is mean but they want 97% interval
1.5% on each tail
in table look up z value for .985

Answer 23

yeah i meant 97...
i think im looking at the z-table incorrectly because i do not see anything past 3.0 on one side and .09 on the other

Answer 24

for p = .985 , z = 2.17

Answer 25

and everything in the middle ranges from .0000 to .4990

Answer 26

oh ok its a diff type of table, for that table you want % from mean to .985
--> .985 - .5 = .485

look up .485

Answer 27

ok that's correct. can you tell me how you got that z value for future reference

Answer 28

i get 2.1 with .485

Answer 29

you have to look at top row to get hundredth value

.00 .01 .02 ..... .07
2.1 ...... .485

Answer 30

ok it makes sense.

Answer 31

can keep asking u questions? ive been working on this hw for a while now and ive been needing help. its due pretty soon too.

Answer 32

its not 14

Answer 33

what is considered capable ? 2 std dev? or 3 std dev?

Answer 34

within bounds

Answer 35

within the lower and upper control limits

Answer 36

so im thinking 2 cause the the two limits are both 14 grams away from the mean

Answer 37

\[z = \frac{14}{\sigma}\]
z is determined by control limits

Answer 38

im still confused about this one :/

Answer 39

i tried using 1.33 as z

Answer 40

1.33sigma=14
/1.33 /1.33
10.53