Question

identify one of the two solutions: x^2+6x-40=0

Answer 1

x^2 + 6x - 40 = 0

Lets find the roots of the equation first which can be 2,20 ad 4,10 and 5,8

But 4,10 will satisfy the equation since (10 -4 = 6)

x^2 + 10x - 4x - 40 = 0

x (x + 10) -4 (x + 10) = 0 [Taking x common]

(x-4) (x + 10) = 0

X - 4 = 0 => x = 4

x + 10 = 0 => x = - 10

So two solutions are x = 4 nd x = -10

Answer 2

so if it says identify one do i just put one of those you gave me ?

Answer 3

Since Root cannot be negative it should be the positive one so ur answer should be x = 4

Answer 4

thanks a lot dude

Answer 5

Anytime !

Answer 6

i have one more lol if u dont mind i have an assingment due at night

Answer 7

Sure np

Answer 8

its the same thing but 4x^2+19x-5=0

Answer 9

Roots would be 20 and 1 which satisfies 20 - 1 = 19

so it would be 4x^2 + 20x - x - 5 = 0

4x (x + 5) -1 (x + 5) = 0
(4x -1) (x + 5) = 0

4x - 1 = 0 => x = 1/4

x + 5 = 0 => x = -5

So if u want to pick one it would be 1/4

Answer 10

so 1/4 is the answer.