Find the inverse of the function.
f(x) = the cube root of quantity x divided by seven. - 9

answers:
f-1(x) = 21(x + 9)

f-1(x) = [7(x + 9)]3

f-1(x) = 7(x3 + 9)

f-1(x) = 7(x + 9)3

Question

Find the inverse of the function.
f(x) = the cube root of quantity x divided by seven. - 9 

answers:
f-1(x) = 21(x + 9) 

 f-1(x) = [7(x + 9)]3 

 f-1(x) = 7(x3 + 9) 

 f-1(x) = 7(x + 9)3

agent0smith · Answer

Can you write it as an equation, not words?

anonymous · Answer

$$\sqrt[3]{x/7}-9$$

agent0smith · Answer

$$\huge y = \sqrt[3]{ \frac{ x }{ 7 } } -9$$solve this for y. Start by adding 9 to both sides.

Then you'll have to cube both sides, to get rid of the cube root.

anonymous · Answer

okay I did that, I don't know how it turns out when you cube it, that parts messing me up

agent0smith · Answer

$$\huge y +9 = \sqrt[3]{ \frac{ x }{ 7 } } $$cubing it does this:$$\huge (y+9)^3 = \frac{ x }{ 7 } $$

anonymous · Answer

oh okay is it, $$f^1(x)=21(x+9)$$?

agent0smith · Answer

No. All you have to do is multiply both sides by 7, then swap x and y.

agent0smith · Answer

Leave the cubed part alone.