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OpenStudy (anonymous):
if a=52 degrees b=9 and c=14 find a to the nearest tenth
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
Hint: use the law of cosines
a^2 = b^2 + c^2 - 2bc*cos(A)
a^2 = 9^2 + 14^2 - 29*14*cos(52)
a = ???
OpenStudy (anonymous):
-20,835?
jimthompson5910 (jim_thompson5910):
hmm not sure how you're getting that
jimthompson5910 (jim_thompson5910):
it might help to replace cos(52) with 0.61566147532566
since cos(52 degrees) = 0.61566147532566
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OpenStudy (anonymous):
ok one minute
OpenStudy (anonymous):
coming out with the same thing
jimthompson5910 (jim_thompson5910):
a^2 = 9^2 + 14^2 - 29*14*cos(52)
a^2 = 9^2 + 14^2 - 29*14*0.61566147532566
a^2 = 81 + 196 - 29*14*0.61566147532566
...
...
...
a = ???
OpenStudy (anonymous):
27.0414432
jimthompson5910 (jim_thompson5910):
81 + 196 - 29*14*0.61566147532566 is equal to 27.0414432
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jimthompson5910 (jim_thompson5910):
so
a^2 = 27.0414432
a = ???
OpenStudy (anonymous):
is it the sqrt of 27.0414432?
jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
what is that?
OpenStudy (anonymous):
5.20013876738
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jimthompson5910 (jim_thompson5910):
good, you got it
jimthompson5910 (jim_thompson5910):
don't forget to round
OpenStudy (anonymous):
thank you so much
jimthompson5910 (jim_thompson5910):
sure thing
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