Question

integrate ∫(4-x)^11 dx
u = 4-x


∫(4-x)^11 dx = ∫u^11 du
= u^12 / 12 + C
rite?

Answer 1

Yes, now sub back in

Answer 2

I think.. >.>

Answer 3

= (4-x)^12 / 12 + C

Answer 4

i looked at the solution

it says that it is:
- ∫u^11 du
why is that?

Answer 5

what's du?

Answer 6

You're wrong shamil.. u=4-x
du=-dx

Answer 7

The integral becomes:
-Int(u^11du)

Answer 8

me no comprende, why though? o.o

Answer 9

u = 4-x right?

Answer 10

yeh

Answer 11

u = 4x^0 - x^1
du/dx = 0*4x^(-1) - 1*x^0

Answer 12

du/dx = -1

Answer 13

Screw it, bah's got it.

Answer 14

oh

Answer 15

du=-dx

Answer 16

ty bah

Answer 17

= -u^12 / 12 + C
= -(4-x)^12/12 + C