Question

Can someone help me solve this integral using inverse trigonometric integrals? I know how to solve it with normal u substitution, but the whole point of the exercise was to use the inverse trigonometric intergrals we learned, so I wanted to see if anyone knew how I could solve it using those.

Answer 1

I don't know, maybe they were trying to show you that you don't always have to use trig sub when you have a radical in the denominator in the form $$\sqrt{a^2 + bx^2}$$

I think it would be somewhat of a nightmare trying to do that with trig sub, are you positive that's how they solved it?

Answer 2

I'm pretty sure that's how she wanted me to solve it, but a lot of the time when she makes her video lessons she's rushing and makes mistakes, so maybe that's it. I just wanted to make sure I wasn't overlooking a way to do it. Thanks!

Answer 3

No problem! :)

Answer 4

Also, for future googlers, that should be $$\sqrt{a^2 \pm bx^2}$$