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Mathematics 16 Online
OpenStudy (anonymous):

help! I dont understand why this is the answer. integrals

OpenStudy (anonymous):

OpenStudy (anonymous):

an explanation would be gt

OpenStudy (anonymous):

great*

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

the answer i got is (5e^x)-(12/x^(2))+c

OpenStudy (anonymous):

i just dont understand where the 12 came from

OpenStudy (anonymous):

\[\int\limits x^{-3}\,dx=\frac{ -x^{-2} }{ 2 }+c\]

OpenStudy (anonymous):

24/2=12

OpenStudy (anonymous):

why did you divide by 2?

OpenStudy (anonymous):

i figured thats how you got the 12 but why 2?

OpenStudy (anonymous):

oops i think i get it

OpenStudy (anonymous):

i feel dumb for asking a simple question

OpenStudy (anonymous):

thanks for the help everyone!

OpenStudy (anonymous):

\[\int\limits x^n\,dx=\frac{ x^{n+1} }{ n+1 }+c \,\,\,\:\forall n \ne 0\]

OpenStudy (anonymous):

@pgpilot326 can you help me with this...i cant seem to get the answer

OpenStudy (anonymous):

OpenStudy (anonymous):

rewrite 23/x as\[23x^{-1}\]

OpenStudy (anonymous):

okay i got that @pgpilot326

OpenStudy (anonymous):

so where's your trouble?

OpenStudy (anonymous):

should it be 23x^0/0?

OpenStudy (anonymous):

oh, my bad... n can't be 1. \[\int\limits x^{-1}\,dx=\int\limits \frac{1}{x}\,dx = \ln|x|+c\]

OpenStudy (anonymous):

i mean -1

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