Mathematics
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OpenStudy (anonymous):
help! I dont understand why this is the answer. integrals
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OpenStudy (anonymous):
OpenStudy (anonymous):
an explanation would be gt
OpenStudy (anonymous):
great*
OpenStudy (anonymous):
@Directrix
OpenStudy (anonymous):
the answer i got is (5e^x)-(12/x^(2))+c
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OpenStudy (anonymous):
i just dont understand where the 12 came from
OpenStudy (anonymous):
\[\int\limits x^{-3}\,dx=\frac{ -x^{-2} }{ 2 }+c\]
OpenStudy (anonymous):
24/2=12
OpenStudy (anonymous):
why did you divide by 2?
OpenStudy (anonymous):
i figured thats how you got the 12 but why 2?
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OpenStudy (anonymous):
oops i think i get it
OpenStudy (anonymous):
i feel dumb for asking a simple question
OpenStudy (anonymous):
thanks for the help everyone!
OpenStudy (anonymous):
\[\int\limits x^n\,dx=\frac{ x^{n+1} }{ n+1 }+c \,\,\,\:\forall n \ne 0\]
OpenStudy (anonymous):
@pgpilot326 can you help me with this...i cant seem to get the answer
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OpenStudy (anonymous):
OpenStudy (anonymous):
rewrite 23/x as\[23x^{-1}\]
OpenStudy (anonymous):
okay i got that @pgpilot326
OpenStudy (anonymous):
so where's your trouble?
OpenStudy (anonymous):
should it be 23x^0/0?
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OpenStudy (anonymous):
oh, my bad... n can't be 1.
\[\int\limits x^{-1}\,dx=\int\limits \frac{1}{x}\,dx = \ln|x|+c\]
OpenStudy (anonymous):
i mean -1