Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@Loser66
OpenStudy (loser66):
where are you stuck?
OpenStudy (anonymous):
i got the answer but...the computer is not accepting it
OpenStudy (anonymous):
i got (-12x^5/5)+(13x^4/4)+c
OpenStudy (loser66):
show me your answer or work, please. You may make mistake at somewhere
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
my answer is above ^ do you see it?
OpenStudy (loser66):
oh yea, if I were the computer, I would say NO to that answer, hihihi..
OpenStudy (anonymous):
lolllllll
OpenStudy (anonymous):
oops
OpenStudy (loser66):
Are you hungry? why did you eat the last term?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i thought it was right...
OpenStudy (anonymous):
lmfao you're funny
OpenStudy (anonymous):
because its technically -23x^0/0
OpenStudy (anonymous):
after doing the integral
OpenStudy (loser66):
who said x = x^0?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (loser66):
it's = -23 ln x
OpenStudy (anonymous):
well it goes from 23x^-1 to 23x^-1*1/-1
OpenStudy (anonymous):
i mean 0 in place of -1
OpenStudy (anonymous):
i tried your answer..it did not work
OpenStudy (loser66):
the whole answer is \[-\frac{12x65}{5}+\frac{13x^4}{4}-23lnx +C\]
If it still says NO. , trash your computer or trash me. hehehe.. the latter option sounds good to you and to me
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (loser66):
sorry x^5 not 65
OpenStudy (anonymous):
yeah it tried it and i keep getting a message saying remember absolute value
OpenStudy (anonymous):
I*
OpenStudy (loser66):
oh, trash me, ln|x|
OpenStudy (anonymous):
it has to be in the most general antiderivative
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
wow it is correct
OpenStudy (anonymous):
is ln always with an absolute?
OpenStudy (loser66):
yea, traaaaash me, \[\huge ln|x|\]
OpenStudy (anonymous):
why isnt 23/x not turned into 23x^-1?
OpenStudy (anonymous):
and then using the product rule
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (loser66):
you ask me, I ask whom? our ancestor- mathematicians said that. We, their offspring, cannot say anything. hehehe... Joking,
because (ln|x|)' = 1/x
OpenStudy (anonymous):
oh so the derivative of ln abs(x) is 1/x and you go backwards?
OpenStudy (loser66):
I remember that my prof said something about this case, I took note carefully. However, I lent my note.
OpenStudy (anonymous):
oh wow thank god i asked you because I would have never known
OpenStudy (loser66):
antiderivative of 1/x = ln x
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
okay so what if it was 1/2x^2?
OpenStudy (anonymous):
would you bring x^2 to the top? and make it x^-2?
OpenStudy (loser66):
apply rule, x ^-2 as usual
OpenStudy (anonymous):
in that case you wouldnt do the ln (x) right?
OpenStudy (anonymous):
so it is only for 1/x?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (loser66):
yup,
yup for the second question
OpenStudy (anonymous):
you. are. amazing.
OpenStudy (anonymous):
thank you...i really appreciate it
OpenStudy (loser66):
crazy
OpenStudy (loser66):
hehehe.. you.are.amazing.crazy.
I add to get the whole sentence. hehehehe ok, good luck