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Mathematics 22 Online
OpenStudy (anonymous):

integral help

OpenStudy (anonymous):

@Loser66

OpenStudy (loser66):

where are you stuck?

OpenStudy (anonymous):

i got the answer but...the computer is not accepting it

OpenStudy (anonymous):

i got (-12x^5/5)+(13x^4/4)+c

OpenStudy (loser66):

show me your answer or work, please. You may make mistake at somewhere

OpenStudy (anonymous):

my answer is above ^ do you see it?

OpenStudy (loser66):

oh yea, if I were the computer, I would say NO to that answer, hihihi..

OpenStudy (anonymous):

lolllllll

OpenStudy (anonymous):

oops

OpenStudy (loser66):

Are you hungry? why did you eat the last term?

OpenStudy (anonymous):

i thought it was right...

OpenStudy (anonymous):

lmfao you're funny

OpenStudy (anonymous):

because its technically -23x^0/0

OpenStudy (anonymous):

after doing the integral

OpenStudy (loser66):

who said x = x^0?

OpenStudy (loser66):

it's = -23 ln x

OpenStudy (anonymous):

well it goes from 23x^-1 to 23x^-1*1/-1

OpenStudy (anonymous):

i mean 0 in place of -1

OpenStudy (anonymous):

i tried your answer..it did not work

OpenStudy (loser66):

the whole answer is \[-\frac{12x65}{5}+\frac{13x^4}{4}-23lnx +C\] If it still says NO. , trash your computer or trash me. hehehe.. the latter option sounds good to you and to me

OpenStudy (loser66):

sorry x^5 not 65

OpenStudy (anonymous):

yeah it tried it and i keep getting a message saying remember absolute value

OpenStudy (anonymous):

I*

OpenStudy (loser66):

oh, trash me, ln|x|

OpenStudy (anonymous):

it has to be in the most general antiderivative

OpenStudy (anonymous):

wow it is correct

OpenStudy (anonymous):

is ln always with an absolute?

OpenStudy (loser66):

yea, traaaaash me, \[\huge ln|x|\]

OpenStudy (anonymous):

why isnt 23/x not turned into 23x^-1?

OpenStudy (anonymous):

and then using the product rule

OpenStudy (loser66):

you ask me, I ask whom? our ancestor- mathematicians said that. We, their offspring, cannot say anything. hehehe... Joking, because (ln|x|)' = 1/x

OpenStudy (anonymous):

oh so the derivative of ln abs(x) is 1/x and you go backwards?

OpenStudy (loser66):

I remember that my prof said something about this case, I took note carefully. However, I lent my note.

OpenStudy (anonymous):

oh wow thank god i asked you because I would have never known

OpenStudy (loser66):

antiderivative of 1/x = ln x

OpenStudy (anonymous):

okay so what if it was 1/2x^2?

OpenStudy (anonymous):

would you bring x^2 to the top? and make it x^-2?

OpenStudy (loser66):

apply rule, x ^-2 as usual

OpenStudy (anonymous):

in that case you wouldnt do the ln (x) right?

OpenStudy (anonymous):

so it is only for 1/x?

OpenStudy (loser66):

yup, yup for the second question

OpenStudy (anonymous):

you. are. amazing.

OpenStudy (anonymous):

thank you...i really appreciate it

OpenStudy (loser66):

crazy

OpenStudy (loser66):

hehehe.. you.are.amazing.crazy. I add to get the whole sentence. hehehehe ok, good luck

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