A gasoline engine with an efficiency of 30% operates between a high temperature T1 and a low temperature T2 = 320K. If this engine operates with Carnot efficiency, what is the high-side temperature T1? can someone please explain this?

Question

anonymous · Answer

Carnot cycle is ation. Evso, it cannot do better than 
efficiency = (Thigh - Tlow)/(Thigh) here = 0.30

(Thigh - 320 K)/Thigh = 0.30 

Solving this gives you Thigh.

0.70 Thigh = 320 K

Thigh =?

anonymous · Answer

Carnot cycle is an idealization, even so it cannot do better than 

etc.  [first line garbled]

anonymous · Answer

thank you