Question

Probability Question.
How many ways can seven people A, B, C, D, E, F, and G sit on a bench if A wants to sit next to B and F wants to sit on one of the ends?

Answer 1

I set up a possibliities chart and came up with
2*6*1*4*3*2*1 and got 288 ways.
It's wrong though.

Answer 2

48 ?

Answer 3

It's supposed to be 480, but thanks anyways.

Answer 4

ah yes, it is 480

case I (F on the right end) :
AB____F = 4! 2!
_AB___F = 4! 2!
__AB__F = 4! 2!
___AB_F = 4! 2!
____ABF = 4! 2!
TOTAL = 5 * 4! * 2! = 240

case II (F on the left side)
FAB____ = 4! 2!
F_AB___ = 4! 2!
F__AB__ = 4! 2!
F___AB_ = 4! 2!
F____AB = 4! 2!
TOTAL = 5 * 4! 2! = 240

240 + 240 = 480 ways

Answer 5

thank you

Answer 6

you're welcome