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find dy/dx at (4,pi/2) if r=2+3sin theta
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\[\frac{ dy }{ dx }at (4,\frac{ \pi }{2 }),, and,, r=2+3\sin \theta \]
are you looking for dy/dx or dr/d(theta) ?
dy/dx
then this is a tricky problem, have you tried it?
OK. You need to use the following.... For r = f(θ) and x=rsinθ y=rcosθ (polar co-ordinates) dy/dx = [(dr/dθ)sinθ +rcosθ]/[(dr/dθ)cosθ - rsinθ)] You just need to find the derivative and plug in the co-ordinate point
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If you're wondering how i got the fancy dy/dx formula i can send you the derivation
By the way the graph doesnt go through (4, pi/2), is this point correct?
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