solve the equation for exact solutions.
sin^-1x+2tan^1x=pi

Question

solve the equation for exact solutions.
sin^-1x+2tan^1x=pi

anonymous · Answer

do you mean sin^-1x+2tan^-1x=pi?

anonymous · Answer

yes

anonymous · Answer

the solution of 1 can be found via guess & check; not sure how to find it algebraically

anonymous · Answer

sorry, im still trying to solve it

anonymous · Answer

is this meant to be solved using calculus?

anonymous · Answer

no we are doing this in trigonometry...dealing with arcsin, arccos, and arctan, my professor likes to switch around problems so its hard to undestand them

alekos · Answer

yes , it can be solved. what have you got?

anonymous · Answer

well what i did is someow move arcsin x to pi...but i dont think that is right

alekos · Answer

doing it in stages we get 

1/sinx + 2/tanx = pi

1/sinx + 2cosx/sinx = pi

(1 + 2cosx)/sinx = pi

1 + 2cosx = pi*sinx

pi*sinx - 2cosx = 1

my mistake, it doesnt come down to a simple solution

let me think about it

anonymous · Answer

ok no problem

alekos · Answer

this can't be solved algebraically, i think you'll need to do it graphically

alekos · Answer

been thinking about this one....

for y = asinx +bcosx

we can find y = Asin(x+c)

where a = Acosc  and b = Asinc

in this case  a=pi and b=-2, so we can solve for A and c

then we solve for  Asin(x+c) =1

and we get    x = arcsin(1/A) - c

give this a try and see what you get