Mathematics
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OpenStudy (anonymous):
what about phase shifts?
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ganeshie8 (ganeshie8):
before talking about trig,
lets quickly consider \(y = x^2\)
OpenStudy (anonymous):
2 sin (x-(pi/3))
OpenStudy (anonymous):
oh ok
ganeshie8 (ganeshie8):
if u shift right by 2 units,
equation befomes : \(y = (x-2)^2\)
ganeshie8 (ganeshie8):
if u shift left by 2 units,
equation befomes : \(y = (x+2)^2\)
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ganeshie8 (ganeshie8):
basically,
if f(x) is the parent graph, and k is +ve then :-
f(x-k) : shifts the graph RIGHT by k units
f(x+k) : shifts the graph LEFT by k units
OpenStudy (anonymous):
so it up 2 right by (pi/3)
ganeshie8 (ganeshie8):
lets not talk about up/down yet.
OpenStudy (anonymous):
ok
ganeshie8 (ganeshie8):
but u got it correct ! it shifts right by pi/3
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ganeshie8 (ganeshie8):
parent graph : sin(x)
your graph : sin(x - pi/3)
so your graph shifts the parent graph RIGHT by pi/3 units ok
OpenStudy (anonymous):
ok
ganeshie8 (ganeshie8):
2 sin (x-(pi/3))
2 here is for Amplitude. Not for shifting up/down
ganeshie8 (ganeshie8):
2 says, that, the graph amplitude is 2
OpenStudy (anonymous):
oh ok got it
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ganeshie8 (ganeshie8):
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