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Mathematics 21 Online
OpenStudy (anonymous):

Mary buys 20 tickets in a lottery that has 5000 tickets altogether find the probability that marry will win second price only?

OpenStudy (perl):

so there is one first prize ticket, and one second prize ticket

OpenStudy (perl):

mary wants the probability of winning second prize (but not first prize), correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

20 /5000 first prize and 19 /4999 is second

OpenStudy (anonymous):

answer is 498/12475

OpenStudy (perl):

so you want to know how they got that answer

OpenStudy (anonymous):

yes plz

OpenStudy (perl):

can you double check thats the answer

OpenStudy (anonymous):

well what's the probability that the first prize won't be picked?

OpenStudy (perl):

4980/5000 * 20/4999

OpenStudy (anonymous):

no i just asked the probability that the first prize won't be picked. how much is that?

OpenStudy (perl):

thats not what he got ,

OpenStudy (perl):

4999/5000

OpenStudy (anonymous):

alright and what's the probability that the second prize WILL be picked?

OpenStudy (perl):

it depends on whether you pick the first prize ticket first or not

OpenStudy (anonymous):

and what is that value?

OpenStudy (perl):

1/ 4999

OpenStudy (perl):

assuming you picked the first prize

OpenStudy (anonymous):

alright then what's the probability that you didn't pick any of the other tickets afterwards?

OpenStudy (perl):

what other prizes are there, it doesnt mention

OpenStudy (anonymous):

there aren't any more. that's what the question tells us

OpenStudy (anonymous):

Guys guys... I think you're looking at this from a wrong point of view. she has a 0.4% chance of winning a ticket. Factor that into your probability.

OpenStudy (perl):

the probability of winning first prize is 1/5000 ,

OpenStudy (anonymous):

srry my comp died yes the answer is right

OpenStudy (perl):

ok i think i have an idea,

OpenStudy (anonymous):

@ayeshaafzal221 you said "19 /4999 is second" given that she did not win first place, why are her chances reduced by one?

OpenStudy (anonymous):

if it asked for 2nd prize, the probability that triton says would be right. when asked ONLY first prize, that's when a lot more values get important

OpenStudy (anonymous):

yes @Triton my bad

OpenStudy (anonymous):

did you get it perl?

OpenStudy (perl):

im not sure

OpenStudy (anonymous):

ohk thank of trying guys , tomorrow i ll ask my teacher

OpenStudy (anonymous):

but that's a 1 in 5000 chance :S

OpenStudy (anonymous):

I have no idea how they got to that.

OpenStudy (anonymous):

its tree diagram question

OpenStudy (anonymous):

the first ticket, to get it was 20 out of 5000. to NOT get it was 4980/5000

OpenStudy (anonymous):

the second ticket, to get it was 20 out of 4999, if the first one WASN'T picked. If it was, 19/4999 but it wasn't so it's the first value

OpenStudy (anonymous):

since the 2nd ticket WAS picked, you only have 19 tickets, but since every ticket after that WASN'T picked you get for the third one, you have to get the probability that every ticket won't be picked after that.

OpenStudy (anonymous):

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