Jason inherited a piece of land from his great-uncle. Owners in the area claim that there is a 45% chance that the land has oil. Jason decides to test the land for oil. He buys a kit that claims to have an 80% accuracy rate of indicating oil in the soil. What is the probability that the land has oil and the test predicts it? how do you solve this?
Denote \(A\) to be the event that oil is present, so \(P(A)=0.45\). Then \(P(A')\), the complement of \(A\), is 0.55. Denote \(K\) to be the event that oil is detected by the kit, so \(P(K)=0.80\) and \(P(K')=0.20\). You are asked to find \(P(A\cap K)\). Use the conditional probability formula, \[P(A|K)=\frac{P(A\cap K)}{P(K)},~~P(K|A)=\frac{P(A\cap K)}{P(A)}\] Of course, you have to determine the conditional probabilities first.
@SithsAndGiggles so what would be the answer here
i suck at putting formulas in calculator
0.09 0.11 0.36 0.44
I must have misspoke/-typed. The test for oil is 80% accurate, meaning that the test is positive 80% of the time if oil is actually present, so \(P(K|A)=0.80\). Then \[P(K|A)=\frac{P(A\cap K)}{P(A)}~~\iff~~0.80=\frac{P(A\cap K)}{0.45}~~\iff~~P(A\cap K)=0.36\]
thank you thank you well helped
yw
@jcr268 Wait what was the answer? I don't understand that formula or how to calculate it.
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