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Chemistry 15 Online
OpenStudy (anonymous):

can any one please help me on this chemistry question? I really appreciated. thank you in advanced. I am giving metals. Write the complete balanced equation for the following reaction: CaCl2 + Na3PO4 yields NaCl + Ca3(PO4)2

OpenStudy (abb0t):

It might help to make a chart.

OpenStudy (abb0t):

|dw:1386613944125:dw|

OpenStudy (anonymous):

Yeah that's what i have.:)

OpenStudy (abb0t):

Take notice that there are not equal number of atoms on both sides. The idea of balancing is to take into account everything that is happening. Why? Because atoms don't just disappear into thin air. They're all accounted for in a chemical reaction. So, to balance, you need to sort of, play around with numbers to give you the same number on both sides. That means, if you have 2 on reactant side, you must also have 2 on product side. If you remember from algreba (distributive property). When you put a 2 in front of an element, it follows the distributive property: For instance, CaCl\(_9\), if I were to add a \(\sf \color{red}{2}\) In front of the CaCl\(_9\), You would actually have 2 Ca atoms and 19 chlorine atoms. Does that make sense?

OpenStudy (abb0t):

Also, if you change one side, you must ALSO make sure that you have the same number on the other side. By adding a 3 on the reactant side of CaCl, you now have 3 Ca and 6 chlorine atoms. But on product side, you only have ONE chlorine, which means, you better change the number on product side. Try it. I can help additionally if you're stuck. But I want you to try it first.

OpenStudy (anonymous):

Is this is ok. This is what I got. |dw:1386615709122:dw|

OpenStudy (anonymous):

so this will be the answer \[3Cal2+2Na3(2PO4)--->6NacL+2Ca3(PO4)^2\]

OpenStudy (anonymous):

this will be

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