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\[3^{5n}=3^{5}(3^{2n})^2\]
Remeber you logarithm rules?
\[x ^{a}=a \times lnx\]
i've never learned that :/
Hmmm... Well, you're learning it now. This is typically the way you solve for variables in the exponent position
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So, first simplify this equation.
Do you know how to do that?
well the best simplification i got was this\[3^{5}=2187^{4n^2}\]
I think you made a mistake there
\[3^{5n}=3^{5}(3^{4n})\]
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\[\frac{ 3^{5n} }{ 3^5 }=3^{4n}\]
Do you see what's going on?
then i get \[3^{n}=3^{4n}\]
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