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Mathematics 6 Online
OpenStudy (anonymous):

Solve for n...? medal will be rewarded!

OpenStudy (anonymous):

\[3^{5n}=3^{5}(3^{2n})^2\]

OpenStudy (anonymous):

Remeber you logarithm rules?

OpenStudy (anonymous):

\[x ^{a}=a \times lnx\]

OpenStudy (anonymous):

i've never learned that :/

OpenStudy (anonymous):

Hmmm... Well, you're learning it now. This is typically the way you solve for variables in the exponent position

OpenStudy (anonymous):

So, first simplify this equation.

OpenStudy (anonymous):

Do you know how to do that?

OpenStudy (anonymous):

well the best simplification i got was this\[3^{5}=2187^{4n^2}\]

OpenStudy (anonymous):

I think you made a mistake there

OpenStudy (anonymous):

\[3^{5n}=3^{5}(3^{4n})\]

OpenStudy (anonymous):

\[\frac{ 3^{5n} }{ 3^5 }=3^{4n}\]

OpenStudy (anonymous):

Do you see what's going on?

OpenStudy (anonymous):

then i get \[3^{n}=3^{4n}\]

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