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OpenStudy (anonymous):
@jigglypuff314 saveee meee
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OpenStudy (anonymous):
OpenStudy (anonymous):
@jigglypuff314 You don't love me anymoree </3
OpenStudy (anonymous):
are you asking for like obtuse, acute stuff like that?
OpenStudy (anonymous):
I got the answer for it already ;3 But can you help with another?
OpenStudy (anonymous):
sure :)
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OpenStudy (anonymous):
OpenStudy (anonymous):
Easy (R to Q) then (R to P) last (P to Q)
OpenStudy (anonymous):
That is incorrect...
OpenStudy (anonymous):
@jigglypuff314 I NEED YOUUUUU
OpenStudy (anonymous):
do you have choices?
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OpenStudy (anonymous):
p then q then r if you want to do some trig you can use the law of cosines
OpenStudy (anonymous):
my guess is from looking though do you know the law of cosines?
OpenStudy (anonymous):
P Q R is correct. I had the answer, i just was making sure :D Thanks for the help!
OpenStudy (anonymous):
then. you need to be able to use the law of cosines. do you know how to do this?
OpenStudy (anonymous):
\[cosA=\frac{ b^2+c^2-a^2 }{ 2bc }\]
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OpenStudy (anonymous):
once you get one angle you can just use law of sines on the whole thing.
\[\frac{ sinA }{ a }=\frac{ sinB }{ b }=\frac{ sinC }{ c }\]
OpenStudy (anonymous):
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