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MIT 18.01 Single Variable Calculus (OCW)
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In the case of: \int sin(x) dx I am wondering if the dx is there denoting that sin(x) is a derivative or if the dx symbol in the case of the integral has something to do with the chain rule.
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\int sin(x) dx is asking for the the value of a derivative of a function with respect to x that equals what's inside the integral. int sin(x) dx means "what function, with respect to x, has a derivative of sin(x)?" in this case, -cos(x) has a derivative of sin(x)... but, don't forget, all derivatives of constants are 0 (no slope - no change in 'y'). int sin(x) dx = -cos(x) + C.
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