Question

How do I find the focus and directrix of the following parabola?
x = (-1/8 )y^2

Answer 1

what method you want to use?

Answer 2

seperate y^2

Answer 3

compare with y^2=4ax
a=your focus

Answer 4

always

Answer 5

medal?

Answer 6

naw... the medal goes to the person that answered first

Answer 7

so
y^2 = 4(-8) x? ..

Answer 8

:")

Answer 9

yep @shamil98

Answer 10

Okay, thank you.
What about the directrix?

Answer 11

x+y^2/8 = 0

Answer 12

I'll give @nincompoop the oppurtunity to answer that!

Answer 13

directx is 2

Answer 14

explain pls bruh

Answer 15

Oh and also is the focus and directrix written in coordinates?

Answer 16

we know that parabola is y = a(x-h)^2 + k correct?

Answer 17

yeah

Answer 18

then the relationships can be shown
y – k = a(x – h)^2
(1/a)(y – k) = (x – h)^2
4p(y – k) = (x – h)^2 <-- conics form of the equation
where 4p = 1/a

Answer 19

how did you get 2 as the directrix, nin?

Answer 20

oh this is still going on :O

Answer 21

once u have focus, and vertex,
directrix goes thru the image of focus

Answer 22

p is your distance between the vertex and focus, which is also the distance between the vertex and directrix

Answer 23

my connection goes in and out