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OpenStudy (anonymous):
Can you apply L'Hopital's Rule multiple times? Also, help with finding the limit of (3x)^(1/3x) algebraically please?
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OpenStudy (kc_kennylau):
as long as it's still \(\dfrac00\) or \(\dfrac\infty\infty\) you can use l'hopital rule as many times as you want
OpenStudy (kc_kennylau):
and what does x tend to?
OpenStudy (anonymous):
Towards infinity again
OpenStudy (kc_kennylau):
you mean \(\Large\lim\limits_{x\rightarrow\infty}(3x)^{\frac13x}\)?
OpenStudy (kc_kennylau):
or \(\Large\lim\limits_{x\rightarrow\infty}(3x)^{\frac1{3x}}\)?
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OpenStudy (anonymous):
The second one, sorry for not clearing that up earlier
OpenStudy (kc_kennylau):
not your fault :)
OpenStudy (kc_kennylau):
try taking the log of that function :)
OpenStudy (kc_kennylau):
remember \(\large x=e^{\ln x}\)
OpenStudy (anonymous):
I'm not quite sure how to do that
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OpenStudy (kc_kennylau):
ok i'll do the first step for you :)
OpenStudy (kc_kennylau):
\[\Large\begin{array}{l}&\lim_{x\rightarrow\infty}(3x)^{\frac1{3x}}\\=&e^{\lim\limits_{x\rightarrow\infty}\ln(3x)^{\frac1{3x}}}\\=&e^{\lim\limits_{x\rightarrow\infty}\frac1{3x}\ln(3x)}\end{array}\]
OpenStudy (kc_kennylau):
now you can apply the l'hopital rule :)
OpenStudy (anonymous):
How would I apply it in this case?
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