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Mathematics 15 Online
OpenStudy (anonymous):

Find an equation of the tangent line to the graph of e^(2x-y)=(x^2)/y at the point (2,4).

OpenStudy (isaiah.feynman):

Differentiate the function implicitly, and find y'. Then evaluate y' at 2.

OpenStudy (isaiah.feynman):

Sorry not at 2, but at that point (2,4)

OpenStudy (anonymous):

I got e^(2x-y)*(2-y')=(2xy-x^(2)y')/y^2. But I don't know how to solve for the y' from there on

OpenStudy (isaiah.feynman):

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