Question

f(x)=ax^3+bx^2+cx+d for which f(-3)=-155, f(-1)=-3, f(1)=5, and f(2)=15

Answer 1

So I guess you have to solve these:
\[-155=ax ^{3}+bx ^{2}+cx+d\]For F(-3)\[-3=ax ^{3}+bx ^{2}+cx+d\]For F(-1)\[5=ax ^{3}+bx ^{2}+cx+d\]For f(1)
And so on...

Answer 2

@ganeshie8 @agent0smith can help. :3

Answer 3

Not helping solve a system of four equations, sorry :P

Answer 4

Not as hard as it looks. Write out the version for f(1) and f(-1). Add them together and you eliminate a and c, so you have d in terms of b. Then take the same two equations and subtract them, eliminating b and d, so you get c in terms of a. Substitute those into the equation for f(2) to get b in terms of a. You also have c in terms of a, and d in terms of b can then be in terms of a, so you just plug all those substitutions into the equation for f(-3) and solve for a, then work backwards to the others.