The figures are similar. What are a) the ratio of the perimeters and b) the ratio of the area of the first figure to the second? Thanks.
Lengths scale as sides, 45/21, areas as sides squared. (45/21)^2.
Im sorry, I dont understand.
Are you implying those are the answers? They dont fit my choices.
both are divisible by 3
15:7
Yes, so a would a) is 15/7
yes, and if the area is also the same 45:21 then the same ratio can be used 15:7
what do you have as your choices?
It would be between 26/19 and 225/49.
because area is always squared
225/49 indicates the ratio 15:7
area is always square (15/7)^2 = 225/49
Oh, awesome. I got stuck when you mentioned the area is always squared but now i see how to do it. Thanks Nin.
yeah laws of exponent \[\left( \frac{ a }{ b } \right)^2 =\frac{ a^2 }{ b^2 }\]
Can i ask you one more ratio question while youre here?
k
Two similar trapezoids have an area of 384c,^2 and 24cm^2. What is their ratio of similarity? Would i just divide them into their smallest form?
correct. first thing is to check whether 384 is divisible by 24, and I think it is you can use that 16:1
in the smallest for itd be 2:1?
form
or 4:1?
would it? there's a huge difference between 384 and 24 the smallest form you can divide them both is by the smallest you have, 24
384/24 = 16/1
so your ratio is 16:1 the reason I asked you to see if you can divide 384 by 24 so that you don't have to go through dividing both sides by 2 or 3 until it is simplified completely
what are your choices?
Right, I understand. My question wants us to go smaller though. a: 1:2 -- not possibility b: 1:4 -- not a possibility c: 2:1 -- not likely d: 4:1 -- my choice. I originally divided them both by 12 to get 32/2.
yeah D
awesome, thanks again!
\[\sqrt{\left( \frac{ 16 }{ 1 } \right)}=\frac{ 4 }{ 1 } \rightarrow \left( \frac{ 4 }{ 1 } \right)^2=\frac{ 16 }{ 1 }\]
ciao for now, I have to study for my exam LAUGHING OUT LOUD
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