A sphere of mass 10kg and radius 0.010m is released from the top of a 1.0meter high inclined plane. What is the speed of the sphere when it reaches the bottom of the inclined plane?
the answer is 3.7m/s but I don't know how to get it
Please, help

Question

A sphere of mass 10kg and radius 0.010m is released from the top of a 1.0meter high inclined plane. What is the speed of the sphere when it reaches the bottom of the inclined plane?
the answer is 3.7m/s but I don't know how to get it
Please, help

schrodingers_cat · Answer

Equate energy for the system so you know that

Kf + Uf = Ki + Ui

1/2mv^2 +1/2Iw^2 = Mgh

1/2(I/R^2 + M)v^2 = MGh

V = (2gh/(1 +(I/MR^2)))^1/2

Hope this Helps :)

loser66 · Answer

cross my fingers, hehehe. I am waiting for help for 1 hour!!!

loser66 · Answer

I got it, Thanks a lot.

anonymous · Answer

Sorry not to have seen this until today. Glad you got it.

loser66 · Answer

thanks for reply anyway.