Question

Please help me:
how to differentiate x(2logx)

answer must be 1+lnx/ln2 I don't know how to get to that answer

Answer 1

product rule ....

Answer 2

[ab]' = a'b + ab'

let a = x
let b = 2logx

Answer 3

also might want to recall the change of base for logs, im assuming that it is stated in base 10?

logx = lnx/ln10

Answer 4

yes but it says 2logx so ln2x/ln10 ?

Answer 5

2 logx = 2 lnx/ln10; which is really jsut a constant times lnx

k lnx derive to k/x

Answer 6

x k lnx

k lnx + x k/x

k(lnx + 1)