Question

Find the areas of the regions enclosed by the lines and curves. y=x^2-2 and y=2

Answer 1

Region is parabola, vertex at x = 0, y= -2

meets y = 2 at x= -2, 2.

Integrating gives area under curve, (1/3)x^3 - 2x.

Can put this all in a square , x from -2 to +2, y from -2 to +2, area = 4x4=16.

Then subtract the two little areas obtained by integration

I got 16 - 8/3 = 40/3, but check my math!