Question

can someone show me how I would go about balancing this equation?

KBrO3(s)  KBr(s) + O2(g)

Answer 1

2 KBrO3(s)= 2KBr(s) + 3O2(g)

Answer 2

do u see how i got that
or do u want me to explain it?

Answer 3

Why didn't you just explain it from the beginning since they are asking "how would go about balancing".

Answer 4

its actually pretty self explanatory

Answer 5

k

Answer 6

Could you please explain?

Answer 7

okay so, first we look at K, since there is only 1 K on both sides we leave it, then we go on Br, and again there is only 1 Br on both sides, so we leave that it as is, Then we look at O (Oxygen), now we have 3 Oxygens on the left side and 2 Oxygens on the right hand side

\[KBrO_{3}(s)= KBr(s)+ O _{2}\]

So now on the left hand side we multiple the compound by 2 since it has 3 oxygens, and on the right hand side we will multiply oxygen by 3 since there are 3 oxygens on the left hand side, also since we multiplied the whole compound on the left hand side by 2, we have 2 K and 2 Br, so we now we also have to multiply KBr on the right hand side by 2. So it will look like this:

\[2 KBrO_{3}--> 2KBr(s)+ 3O _{2}\]

This is now Balanced because we now have 2 KBr, on the left and right, 6 Oxygens on the left and right.
if you have any question feel free to ask